Python Slip 3

Q1. Write a python program to show use of finally clause of exception handling. Solution:

In [ ]:

try:
    numerator = 10
    denominator = 0
    result = numerator/denominator
    print(result)
except:
    print("Error: Denominator cannot be 0.")
    
finally:
    print("This is finally block.")

In [ ]:

Another Solution:

try:
    print('try block')
    x=int(input('Enter a number: '))
    y=int(input('Enter another number: '))
    z=x/y
except ZeroDivisionError:
    print("except ZeroDivisionError block")
    print("Division by 0 not accepted")
else:
    print("else block")
    print("Division = ", z)
finally:
    print("finally block")
    x=0
    y=0
print ("Out of try, except, else and finally blocks." )

Q2. Write a program that returns a list that contains only the elements that are common between the lists (without duplicates). Make sure your program works on two lists of different sizes. Solution:

In [ ]:

one = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13]
two = [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]
both=[]
if len(one) < len(two):
    for i in one:
        if i in two and i not in both:
            both.append(i)      
if len(one) > len(two):
    for i in two:
        if i in one and i not in both:
            both.append(i)
print(both)

Q2. Write a python program which accepts file name and word to be searched in file. Display line numbers which contain given word and total occurrences of it. Suppose sample file is test.txt and it contains Rahul Sonawane November july may march june Tal nsk Rahul Dist Nashik Rahul

In [ ]:

fname = input("Enter file name: ")
word=input("Enter word to be searched:")
k = 0
 
with open(fname, 'r') as f:
    for line in f:
        words = line.split()
        for i in words:
            if(i==word):
                k=k+1
print("Occurrences of the word:")
print(k)