a) Create a random array of n integers. Accept a value x from user and use linear search algorithm to check whether the number is present in the array or not and output the position if the number is present.
Solution:
#include<stdio.h>
int linear_search(int *a,int n,int ele)
{
int i,flag=0;
for(i=0;i<n;i++)
{
if(a[i]==ele)
return i;
}
return -1;
}
void generate(int *a, int n)
{
int i;
for(i=0;i<n;i++)
a[i]=rand()%100;
}
void display(int *a,int n)
{
int i;
for(i=0;i<n;i++)
{
printf("%d\t",a[i]);
}
}
main()
{
int a[20],i,j,n,x,ans;
printf("\n Enter how many elemants:");
scanf("%d",&n);
generate(a,n);
printf("\n Elements are:\n");
display(a,n);
printf("\n Enter searching element : ");
scanf("%d",&x);
ans=linear_search(a,n,x);
if(ans==-1)
printf("\n %d is NOT found.",x);
else
printf("\n %d is found at %d position\n",x,ans+1);
}
0 Comments:
Post a Comment